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保姆级 Tomcat 快速入门

时间:2010-12-5 17:23:32  作者:数据库   来源:系统运维  查看:  评论:0
内容摘要:复制<projectxmlns="http://maven.apache.org/POM/4.0.0"xmlns:xsi="http://www.w3.org/2001/XMLSchema-in

保姆级 Tomcat 快速入门
保姆复制<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">      <modelVersion>4.0.0</modelVersion>      <groupId>com.tian.maven</groupId>      <artifactId>my-web-maven</artifactId>      <packaging>war</packaging>      <version>1.0-SNAPSHOT</version>      <name>my-web-maven Maven Webapp</name>      <url>http://maven.apache.org</url>      <dependencies>        <dependency>          <groupId>junit</groupId>          <artifactId>junit</artifactId>          <version>3.8.1</version>          <scope>test</scope>        </dependency>        <dependency>          <groupId>javax.servlet</groupId>          <artifactId>javax.servlet-api</artifactId>          <version>3.1.0</version>        </dependency>      </dependencies>      <build>        <finalName>my-web-maven</finalName>      </build>    </project>  1.2.3.4.5.6.7.8.9.10.11.12.13.14.15.16.17.18.19.20.21.22.23.24.25.26.
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